Error |
Name | Description | |
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Dawson(Double) |
Dawson(x) evaluates Dawson's integral for a double precision real argument x.
C# 2 / x 2 -x | t F(x) = e | e dt | / 0 | |
Dawson(Double, Boolean) |
Dawson(x) evaluates Dawson's integral for a double precision real argument x.
C# 2 / x 2 -x | t F(x) = e | e dt | / 0 |